Lines & systems
Systems by elimination
ALEKS placement
Scale the equations until one variable has opposite coefficients, then add them.
What this covers
- Line up like terms in both equations: x under x, y under y, plain numbers under plain numbers.
- Pick the letter to cancel: the one with the smaller numbers, or one whose coefficients already match or are opposites.
- Multiply one or both equations so that letter's coefficients are opposites. Multiply every term, the right side too.
- Add the equations straight down. Each equation balances, so adding left to left and right to right keeps the balance.
- Solve for the surviving letter, then substitute back for the other.
- Check the pair in the equation you did not use for the back-substitution.
Reach for this when both equations are already in ax + by = c form and no variable is alone — especially when the coefficients are awkward numbers, since scaling avoids the fractions substitution would create. If one equation already reads y = something, substitution is faster.
Worked example
Solve 2x + 3y = 12 and 4x - y = 10.
- 12x−3y=30Multiply the second equation by 3 so the y terms will cancel.
- 14x=42Add it to 2x + 3y = 12.
- x=3,y=2Divide, then substitute back.
Solve 3x + 2y = 8 and 2x − 3y = 1.
- 9x+6y=24Multiply every term of the first equation by 3, including the right side.
- 4x−6y=2Multiply every term of the second equation by 2. Now the y coefficients, 6 and −6, are opposites.
- 13x=26Add the two new equations. The y terms cancel.
- (x,y)=(2,1)Divide by 13 to get x = 2. Then 3(2) + 2y = 8 gives y = 1. Check: 2(2) − 3(1) = 1.
A common mistake
From 4x−y=10
“Multiplying an equation by 3 multiplies every term, the constant too: 3 · 4x = 12x, 3 · (−y) = −3y and 3 · 10 = 30. Leaving 10 as it was makes a different equation.”
Try one
Solve the system. Enter the ordered pair (x, y).
{x+y=−8x−y=−4Practice elimination free
No account, no email. Every line you type is checked by the same computer algebra system as the worked example above.
Where this fits
Before this