Lines & systems
Systems by substitution
ALEKS placement
Solve one equation for one variable, then substitute that expression into the other.
What this covers
- Pick the equation and variable with a coefficient of 1 or -1.
- Isolate that variable.
- Substitute the whole expression — in parentheses — into the other equation.
- Solve, then back-substitute for the second variable.
Reach for this when a variable is already alone on one side, or when some variable has a coefficient of 1 or -1 so isolating it costs nothing. If every coefficient is a number like 3 or 7, isolating creates fractions — use elimination instead.
Worked example
Solve y = 2x - 1 together with 3x + y = 9.
- 3x+(2x−1)=9Replace y with its expression, in parentheses.
- 5x=10⇒x=2Combine and divide.
- y=2(2)−1=3Back-substitute into the isolated equation.
Solve x = 3y − 11 and x + y = 1.
- (3y−11)+y=1The first equation gives x, so replace x with the whole expression 3y − 11. Either variable can be the one replaced.
- y=3Combine the y terms to get 4y − 11 = 1. Add 11 to both sides, then divide by 4.
- x=3(3)−11=−2Put y = 3 back into x = 3y − 11. Check: −2 + 3 = 1.
A common mistake
From 3x+(2x−1)=9
“Combining 3x + (2x − 1) gives 5x − 1 = 9. Clearing the −1 means adding 1 to both sides: 9 + 1 = 10, so 5x = 10. Writing 5x = 9 dropped the −1 from the left without doing anything to the right.”
Try one
Solve the system. Enter the ordered pair (x, y).
{y=x−4x+y=−2Practice substitution free
No account, no email. Every line you type is checked by the same computer algebra system as the worked example above.
Where this fits
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